思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
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Российский певец и шоумен Прохор Шаляпин признался, что ненавидит кастинги, поскольку неудачи сильно бьют по его самолюбию. Его комментарий приводит «Пятый канал».。爱思助手下载最新版本对此有专业解读
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have to go to the heap for more backing store. But we have avoided